How to calculate of Hydraulic Power Pack

Hydraulic Press Machine

A hydraulic power pack is a device that transforms mechanical energy into hydraulic energy. It powers hydraulic machines like hydraulic cylinders, hydraulic motors, and hydraulic valves. The hydraulic power pack's operation is based on Pascal's Law, which states that when pressure is applied to a fluid in a closed system, pressure is transmitted equally in all directions.

An electric motor or engine, a hydraulic pump, a reservoir, and various control valves comprise a typical hydraulic power pack. The hydraulic pump is powered by an electric motor or engine, which creates a flow of hydraulic fluid that is stored in a reservoir. The hydraulic fluid is then routed to various hydraulic components via a series of control valves that regulate the fluid's flow and direction.

The hydraulic fluid, typically oil, is pressurised by the pump and then directed through the system to the hydraulic component that needs to be powered. Hydraulic fluid enters the component, such as a hydraulic cylinder, and moves it. The component's movement generates mechanical energy, which can be used to do work.

The hydraulic power pack is intended to supply the system with a constant flow and pressure of hydraulic fluid. This ensures that the hydraulic component is consistently and reliably powered, which is critical in many industrial applications. The hydraulic power pack's size and capacity are determined by the specific requirements of the hydraulic system it is intended to power.

A hydraulic power pack works on the principle of converting mechanical power into hydraulic power. A hydraulic power pack is made up of a motor, a pump, a reservoir, valves, and other hydraulic parts. The motor generates mechanical power, which drives the pump, which pressurises the hydraulic fluid in the reservoir. The pressurised fluid is then routed through valves and hydraulic hoses to power a cylinder, motor, or other hydraulic device.

The hydraulic power pack operates on the principle of Pascal's law, which states that pressure applied to a fluid in a closed container is transmitted equally and unequally to all parts of the container and the fluid. The pressurised hydraulic fluid in the hydraulic power pack transmits force to the hydraulic equipment, which converts the hydraulic power back into mechanical power.

Hydraulic power packs are used in a variety of industrial applications where high force and precise control are required. Some common applications include lifting and lowering heavy loads, powering hydraulic presses and machinery, and controlling the movement of large hydraulic cylinders.

Hydraulic power pack critical parameters

The following critical parameters must be determined before designing a hydraulic power pack:

·        1 Flow rate: The required flow rate is determined by the size of the actuator and the speed at which it must operate. Flow rate is usually estimated as Q = VA, where is the flow rate, is the velocity, and A is the area of the act.

·        2. Pressure: The required pressure is determined by the load and the actuator's size. Use the formula P = F/A to compute the pressure, where P represents the pressure, F represents the force, and A indicates the area of the act.

·        3. Hydraulic power: the quantity of power needed is governed by the size and speed of the act. P = QP is used to determine hydraulic power, where P denotes hydraulic power, flow rate, and pressure.

·        4. Pump size: Once you've determined the required flow rate and pressure, you may select the appropriate size pump to generate the required power.

·        5. Reservoir size: The reservoir should be large enough to hold the fluid in the system while also allowing for expansion.

·        6. Actuator size: The size of the actuator will be determined by the load and speed requirements of the system.

With these factors, you can construct a hydraulic power pack that will fulfil the needs of your. It is also critical to get high-quality components and guarantee that the system is adequately and properly fitted.

 

What are the essential components of a hydraulic power pack

A simple hydraulic power item list is shown below:

• ·        Hydraulic reservoir tank
• ·        Electric motor or engine
• ·        Hydraulic pump
• ·        Valves: control valve relief valve, check valve directional control valve
• ·        Pressure gauge
• ·        Hydraulic cooler
• ·        Hydraulic hoses fittings
• ·        Filter suction filter or pressure filter on the application
• ·        exchanger or oil heater

        The particular components required will vary depending on the particular application and needs of the hydraulic system.

 

What applications do hydraulic power packs have in industry?

        Hydraulic power packs are used in a variety of industrial applications that require high-powered equipment. Here are some applications for power packs:

• handling equipment such as cranes, lifters, and conveyors.
• Mining and construction equipment such as excavators, loaders, and bulldozers.
• Industrial presses, such as stamp presses and extruders.
• Manufacturing equipment such as injection moulding machines, die casting      machines, and forging presses.
• testing equipment used to determine the strength and dependability of materials such as pipes, pumps, and valves.

        Hydraulic power packs are preferred over other sources of energy such as electrical power or fossil fuels because they provide precise control and high power output, making them suitable for demanding applications.

Type of Press	C-frame type, down stroke
Max. Force.	25 Ton
Stroke.	600 mm
Cylinder Bore. (D)	140 mm
Cylinder Rod (d).	100 mm
Fast Approach Speed	100 mm/sec = 6 m/min.
Pressing Speed.	15 mm/ sec. = 0.9 m/min.
Return Speed.	200 mm/ sec =. 12 m/min.
Working Pressure	163 kg/cm2

Forward. Stroke area.   =   0.01639 m3

Downward stroke area. = 0.007543 m3

Now we are require discharge is

Q fast = . Area x velocity

Q fast =. 0.01539 x 6 = 0.9234 m3

Q fast = 92.34 LPM

Q pressings = . Area x velocity

Q pressings =. 0.01539 x 0.9 = 0.013851 m3

Q pressings = 13.85 LPM

Q return =. Area x velocity

Q return = 0.007542 x 12 = 0.09050 m3

Q return = 90.5 LPM

               Machine power selection is also depend on machine operation sequence and cylinder mounting position. In this machine ram will be down in fast speed with in no-load condition. It is use oil pressure is 35 kg/cm2. But pressing time machine will be down in a slow speed with full load then we will use oil pressure is 163 Kg/cm2Now Power require is

P = ( LPM x working pressure) / (612 x efficiency)

P pressing    =  (13.85 x 163)/(612 x .8)

P pressing.   =  4.6 KW

P fast           =  (92.34 x 35)/(612 x .8)

P pressing    =  6.7 KW

P return        =  (90.5 x 35)/(612 x .8)

P return        =  6.47 KW 

         System require min power. Is 6.7 KW but we select standard Motor is 7.5KW.Finally we can select the power

              Further, in this. System require a special type of pump very. It is use a double Vane pump and which capacity range is 95 Lpm in 35 kg/cm2 (high flow with low pressure) + 15 LPM in 163 kg/cm2 (low flow with high pressure)

finally we select a pump model is PVR-50150-FF-13-70 (yuken make)

Tank Oil Capacity     =  oil flow x 3.5

                                  =  92.34 x 3.5 =  323.19 liter

                                  =  325 liter approximately is a oil tank volume